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^3+4Y^2-21Y=0
We add all the numbers together, and all the variables
4Y^2-21Y=0
a = 4; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·4·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*4}=\frac{0}{8} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*4}=\frac{42}{8} =5+1/4 $
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